Let A,B∈R3×3. Suppose that det(A)=2 and det(B)=4. What is det(2ATB−1)?
The answer is 4.
Since A and B are 3×3 matrices, the product ATB−1 is also 3×3. Hence, det(2ATB−1)=23det(ATB−1)=8det(AT)det(B−1)=8det(A)/det(B)=2⋅8/4=4.