In the expression 2[−102−2]−[1243]=[−3a0b], what is a−b?
The answer is 5.
Note that 2[−102−2]−[1243]=[−204−4]+[−1−2−4−3]=[(−2)+(−1)0+(−2)4+(−4)(−4)+(−3)]=[−3−20−7].
Therefore, a=−2 and b=−7 and a−b=−2−(−7)=−2+7=5.