Let z=3cis2. What is the imaginary part of z rounded to 5 decimal places?
The answer is 2.72789.
The imaginary part is given by 3sin2=2.72789228…≈2.72789.
Let z=−1−3i. Which of the following is the polar form of z?
4cis4π3
2cisπ3
2cis4π3
The answer is C.