Let \(z = 2i\) and \(w = 4+i\). What is the imaginry part of \(z+w\)?
The answer is \(3\) since \(z+w = 2i + 4+i = 4 + 3i\).
What is the real part of \((1+i)(3-2i)\)?
The answer is \(5\) since \((1+i)(3-2i) = 3-2i+3i-2i^2 = 3+i-2(-1) = 5+i\).