next up previous
Next: About this document

School of Mathematics and Statistics
Carleton University
Math. 69.104

ASSIGNMENT 1
SOLUTIONS
Due: October 19, 1999 (or Oct.18,1999 Mr. Dubé),

  1. [10] Let a > b be two real numbers. Using any method, evaluate the following limit:

    displaymath206

    .

    Solution There are two cases, namely, a=0 and tex2html_wrap_inline210 .

    Case 1 If tex2html_wrap_inline210 then we can use L'Hospital's Rule. Indeed, in this case,

    displaymath214

    Case 2 On the other hand, if a =0, then we rationalize the numerator (since we cannot use L'Hospital's Rule here since the ``derived limit" does not exist ...) to find,

    displaymath218

    since -b = |b| when b < 0, by definition. Now as tex2html_wrap_inline224 the last limit does not exist as we have different left- and right-hand limits at x = 0, namely, tex2html_wrap_inline228 and tex2html_wrap_inline230 respectively. Hence the limit does not exist if a=0. Combining these results we get that

    displaymath202

  2. [5]a)
    Let tex2html_wrap_inline238 Find the derivative of f, i.e., tex2html_wrap_inline242 , using any method whatsoever.

    Solution The Box method is easiest. Let tex2html_wrap_inline244 . Then, by the Chain Rule,

    displaymath246

    But

    displaymath248

    It follows that

    displaymath250

    [5]b)
    Evaluate tex2html_wrap_inline252 to 3 significant digits.

    Solution 0.605

  3. [5]a)
    Without finding its derivative, determine the number of real roots of the derived polynomial function tex2html_wrap_inline242 where

    displaymath256

    Solution Since this is a polynomial of degree 4 (in disguise), its derivative must be of degree 3 (since its leading coefficient is 1) and so, by the Fundamental Theorem of Algebra, it can have at most three roots. That there are 3 real roots follows from part (b) below.

    [5]b)
    Determine intervals containing the roots in (a).

    Solution Use Rolle's Theorem applied to the function f(x). Note that f(1) =0 and f(2) = 0. Hence it's derivative, tex2html_wrap_inline264 somewhere in the open interval (1,2). A similar argument applied to the intervals (2,3) and (3,4) shows that tex2html_wrap_inline264 somewhere in these intervals too. Hence the three roots belong to the intervals (1,2), (2, 3), (3,4).

    Hint: Use Rolle's Theorem.

  4. Find the derivatives of the following functions using any method.
    [5] a)
    tex2html_wrap_inline276 ,

    Solution Apply the natural logarithm to both sides and use implicit differentiation along with the Product Rule. We get,

    displaymath278

    and so

    displaymath280

    Solving for tex2html_wrap_inline242 we get

    displaymath284

    [5] b)
    tex2html_wrap_inline286

    Solution Use the Box method, for example. Then

    displaymath288

  5. Evaluate the following limits (Show all work).
    [5] a)
    tex2html_wrap_inline290 .

    Solution L'Hospital's Rule is best.

    displaymath292

    [5] b)
    tex2html_wrap_inline294 .

    Solution Note that tex2html_wrap_inline296 , by definition of the principal part of the Arctangent function. Thus the required limit must be 0.

  6. [10] It is known that barometric pressure p changes with altitude h according to the law

    displaymath302

    where tex2html_wrap_inline304 denotes normal pressure (given at the outset) and c is a constant. At an altitude of 5540 meters the pressure is found to be equal to one-half the value of normal pressure. Find the rate of change of the barometric pressure with respect to altitude. Hints: Verify that the Law is really an exponential law ``in disguise". Now proceed as in the derivation of the Law of Radioactive Decay and find c given that At an altitude of 5540 meters the pressure is found to be equal to one-half the value of normal pressure. Your final answer should look like

    displaymath314

    where you need to find c explicitly.

    Solution Apply the exponential function to both sides to find

    displaymath318

    or, equivalently,

    displaymath320

    We are given that when h = 5540 then tex2html_wrap_inline324 . Using this in the last display gives

    displaymath326

    which, when solved for c, gives tex2html_wrap_inline330 . It follows that

    displaymath332

Total: /60


next up previous
Next: About this document

Angelo Mingarelli
Fri Dec 3 13:30:33 EST 1999